(x^2-9)/(x^4-81)

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Solution for (x^2-9)/(x^4-81) equation: 


D( x )

x^4-81 = 0

x^4-81 = 0

x^4-81 = 0

1*x^4 = 81 // : 1

x^4 = 81

x^4 = 81 // ^ 1/4

abs(x) = 3

x = 3 or x = -3

x in (-oo:-3) U (-3:3) U (3:+oo)

(x^2-9)/(x^4-81) = 0

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in { 3} 

x in { -3} 

x belongs to the empty set

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